Method Overloading or Method Overriding

OverridingDemo.java

class Parent
{
   public void show(int... i)
   {
    System.out.println("parent");
   }
}


class Child extends Parent
{
    public void show(int[] i)
    {
      System.out.println("child");
    }
}

public class OverridingDemo
{
    public static void main(String[] args)
     {
       Child c = new Child();
       int arr[]=new int[]{2,3};
       c.show(arr);//child
       c.show(2,3,4);//error
     }
}

Answer:-       Its method Overriding.
int[] i and int …i  both internally represents an Array.

The only difference is
while calling show(int[] i) you have to pass array/null.You cannot pass no of arguments to it
But while calling show(int … i),You can pass array or any number of arguments,or null

As the method is overrided,any call to c.show(-),will always invoke show(int[] i),and if you pass integer array,it works fine.
Else compile time error

Caution:-
In JDK build 1.7.0_03-b05,Its output is as explained above.
In JDK build 1.6.0_32-b05,There is no error which calling c.show(2,3,4),and it gives child as ouput
In JDK build 1.5.0_10-b03,show(int …) & show(int a[]) are treated as same,so it wont allow overriding,because both the show() are treated as same,and you cannot have 2 method with same signature